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Start your free trialVic Mercier
3,276 PointsWhy if I remove the else clause, my li will stay to the bold font-weight?
I find that strange
const laws = document.getElementsByTagName('li');
const indexText = document.getElementById('boldIndex');
const button = document.getElementById('embolden');
button.addEventListener('click', (e) => {
const index = parseInt(indexText.value, 10);
for (let i = 0; i < laws.length; i += 1) {
let law = laws[i];
// replace 'false' with a correct test condition on the line below
if (pareInt(indexText.value) === i) {
law.style.fontWeight = 'bold';
} else {
law.style.fontWeight = 'normal';
}
}
});
<!DOCTYPE html>
<html>
<head>
<title>Newton's Laws</title>
</head>
<body>
<h1>Newton's Laws of Motion</h1>
<ul>
<li>An object in motion tends to stay in motion, unless acted on by an outside force.</li>
<li>Acceleration is dependent on the forces acting upon an object and the mass of the object.</li>
<li>For every action, there is an equal and opposite reaction.</li>
</ul>
<input type="text" id="boldIndex">
<button id="embolden">Embolden</button>
<script src="app.js"></script>
</body>
</html>
1 Answer
Raffael Dettling
32,999 PointsIn the if statment you have to check if the declared index "i" is euqal to the variable index which changes the string to an int with parseInt()
i == index