Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript JavaScript Numbers The Math Object Random Number Challenge – Two Numbers Solution

Aaron Thomas
seal-mask
.a{fill-rule:evenodd;}techdegree
Aaron Thomas
Full Stack JavaScript Techdegree Student 13,189 Points
Posted by Aaron Thomas
.a{fill-rule:evenodd;}techdegree
Aaron Thomas
Full Stack JavaScript Techdegree Student 13,189 Points

why not use a "let" statement for the first and second sections? Then simply overwrite the code?

here is what I did...

// Collect input from a user

let userNum1 = prompt('Type a number. This will be your lowest.');

let userNum2 = prompt('Type a number. This will be your highest.');

// Convert the input to a number

userNum1 = parseInt(userNum1);

userNum2 = parseInt(userNum2);

The code runs just fine and works just like in the video. I want to know if this is actually bad practice or if this creates a problem I'm just not aware of at the moment. It seems to me unnecessary to store the "parseInt() " value into another variable when we can just overwrite the original variable.

1 Answer

Julie Branyan
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Julie Branyan
Full Stack JavaScript Techdegree Graduate 16,337 Points
Julie Branyan
.a{fill-rule:evenodd;}techdegree seal-36
Julie Branyan
Full Stack JavaScript Techdegree Graduate 16,337 Points

Hi Aaron - The variable let will work in this instance you showed above, however if you want to use the original inputLow or inputHigh variable in a different way, you've already reassigned it to a different value and can no longer use the input. const prevents a value from being inadvertently reassigned and makes it clear how its being used in the code. This is beneficial in larger projects from preventing confusion on what the variable is assigned. I like the article below from medium that gives a little more detail.

https://medium.com/javascript-scene/javascript-es6-var-let-or-const-ba58b8dcde75